2023年10月26日之前的作业
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								作业/数字逻辑及实验-李丙栋/实验报告/实验2.pdf
									
									
									
									
									
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								作业/数字逻辑及实验-李丙栋/实验报告/实验2.pdf
									
									
									
									
									
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								作业/数字逻辑及实验-李丙栋/第一章作业-订正.pdf
									
									
									
									
									
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								作业/数字逻辑及实验-李丙栋/第一章作业-订正.pdf
									
									
									
									
									
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								作业/数字逻辑及实验-李丙栋/第一章作业.pdf
									
									
									
									
									
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								作业/数字逻辑及实验-李丙栋/第一章作业.pdf
									
									
									
									
									
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								作业/数字逻辑及实验-李丙栋/第二章作业.pdf
									
									
									
									
									
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								作业/数字逻辑及实验-李丙栋/第二章作业.pdf
									
									
									
									
									
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								作业/数学分析III-顾青/第三周仿写作业.pdf
									
									
									
									
									
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								作业/数学分析III-顾青/第三周仿写作业.pdf
									
									
									
									
									
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								作业/数据结构-金健/10213903403第一章作业.pdf
									
									
									
									
									
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								作业/数据结构-金健/10213903403第一章作业.pdf
									
									
									
									
									
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								作业/数据结构-金健/10213903403第二章作业.pdf
									
									
									
									
									
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								作业/数据结构-金健/10213903403第二章作业.pdf
									
									
									
									
									
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								作业/数据结构-金健/JavaScript/第一章作业1.1.js
									
									
									
									
									
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								作业/数据结构-金健/JavaScript/第一章作业1.1.js
									
									
									
									
									
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const readline = require("readline");
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const rl = readline.createInterface(
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    process.stdin, process.stdout
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);
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let student_num = 10;
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let grades = new Array(student_num); // 类似于C/C++中数组的数据结构,空间复杂度O(n)
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function input(remain_times) {
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    if (remain_times <= 0) {
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        rl.close();
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        return;
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    }
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    rl.question("", (answer) => {
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        grades[student_num - remain_times] = parseFloat(answer); // 暂时不考虑输入错误
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        input(remain_times - 1);
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    });
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}
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rl.on("close", () => {
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    let sum = grades.reduce((sum, current) => {
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        return sum + current;
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    }, 0); // 时间复杂度O(n)
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    let average = sum / student_num;
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    console.log("平均分为:", average);
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});
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rl.write("输入"+student_num+"名学生的成绩,一个一行:\n");
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input(student_num);
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// 输入10名学生的成绩,一个一行:
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// 1
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// 2
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// 3
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// 4
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// 5
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// 6
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// 7
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// 8
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// 9
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// 10
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// 平均分为: 5.5
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								作业/数据结构-金健/JavaScript/第一章作业1.2.js
									
									
									
									
									
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								作业/数据结构-金健/JavaScript/第一章作业1.2.js
									
									
									
									
									
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							@ -0,0 +1,40 @@
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const readline = require("readline");
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const rl = readline.createInterface(
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    process.stdin, process.stdout
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);
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let student_num = 10;
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let grades = new Array(student_num); // 类似于C/C++中数组的数据结构,空间复杂度O(n)
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function input(remain_times) {
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    if (remain_times <= 0) {
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        rl.close();
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        return;
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    }
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    rl.question("", (answer) => {
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        grades[student_num - remain_times] = parseFloat(answer); // 暂时不考虑输入错误
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        input(remain_times - 1);
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    });
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}
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rl.on("close", () => {
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    let sum = grades.reduce((sum, current) => {
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        return sum + current;
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    }, 0); // 时间复杂度O(n)
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    let average = sum / student_num;
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    console.log("高于平均分的学生成绩为:", grades.filter((grade) => grade > average)); // 时间复杂度O(n)
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});
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rl.write("输入"+student_num+"名学生的成绩,一个一行:\n");
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input(student_num);
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// 输入10名学生的成绩,一个一行:
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// 1
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// 2
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// 3
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// 4
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// 5
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// 6
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// 7
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// 8
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// 9
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// 10
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// 高于平均分的学生成绩为: [ 6, 7, 8, 9, 10 ]
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								作业/数据结构-金健/JavaScript/第二章作业1.js
									
									
									
									
									
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								作业/数据结构-金健/JavaScript/第二章作业1.js
									
									
									
									
									
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							@ -0,0 +1,94 @@
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const readline = require("readline");
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const rl = readline.createInterface(process.stdin, process.stdout);
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class Node {
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    previous;
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    value;
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    next;
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}
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class LinkList {
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    head;
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    length;
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    constructor(length) {
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        // 还是需要头结点,此时head表示其中第0个结点,length必须大于0
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        this.length = length;
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        this.head = new Node();
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        // this.head.value = 1;
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        let current, previous = this.head;
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        for (let i = 1; i <= this.length; i++) {
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            current = new Node();
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            current.value = i;
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            previous.next = current;
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            current.previous = previous;
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            previous = current;
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        }
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        current.next = this.head.next;
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        this.head.next.previous = current;
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        // this.head.next = this.current; // 不能多重赋值,赋值语句会返回undefined
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        this.head.previous = current;
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    }
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    remove(node) {
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        node.previous.next = node.next;
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        node.next.previous = node.previous;
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        // delete node; // JavaScript里应该无法直接删除
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        this.length--;
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        return true;
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    }
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    // 找到从当前结点开始第n个结点(可以为负数),当前结点是第0个
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		||||
    // 并且再向后返回一个结点
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    get_n_after_node(node, n) {
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        let property_name = "next";
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        if (n < 0) {
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            property_name = "previous";
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            n = -n;
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        }
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        if (this.length < 3) return false;
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        for (let i = 0; i < n; i++) { // 向后走n个,例如从0开始,到3结束
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            node = node[property_name];
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        }
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        return node;
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    }
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}
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function main(people_num, num1) {
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    let link_list = new LinkList(people_num);
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    let current = link_list.head;
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    let temp;
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    while (true) {
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        temp = link_list.get_n_after_node(current, num1);
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        if (!temp) break;
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        current = temp;
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        link_list.remove(current);
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    }
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    // 此时current是最后一个被删掉的结点,它的next和previous都是存在的结点
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    current = current.next;
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    link_list.head.next = current;
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    for (let i = 0; i < link_list.length; i++) {
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        console.log(current.value);
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        current = current.next;
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    }
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}
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function input(prompt) {
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    return new Promise((resolve) => {
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        rl.question(prompt, (answer) => {
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            resolve(answer);
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        });
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    });
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}
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async function main_() {
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    people_num = parseInt(await input("输入人数"));
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    num1 = parseInt(await input("输入第一个数字"));
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    main(people_num, num1);
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    rl.close();
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}
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main_()
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// 输入人数41
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// 输入第一个数字3
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// 16
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// 31
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								作业/数据结构-金健/JavaScript/第二章作业2.js
									
									
									
									
									
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								作业/数据结构-金健/JavaScript/第二章作业2.js
									
									
									
									
									
										Normal file
									
								
							@ -0,0 +1,135 @@
 | 
			
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const readline = require("readline");
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		||||
const rl = readline.createInterface(process.stdin, process.stdout);
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		||||
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		||||
class Node {
 | 
			
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    previous;
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		||||
    value;
 | 
			
		||||
    next;
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		||||
}
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		||||
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		||||
class LinkList {
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		||||
    head;
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		||||
    length;
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		||||
    constructor(length) {
 | 
			
		||||
        // 还是需要头结点,此时head表示其中第0个结点,length必须大于0
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		||||
        this.length = length;
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		||||
        this.head = new Node();
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		||||
        // this.head.value = 1;
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		||||
        let current, previous = this.head;
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		||||
        for (let i = 1; i <= this.length; i++) {
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		||||
            current = new Node();
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		||||
            current.value = i;
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		||||
            previous.next = current;
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		||||
            current.previous = previous;
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            previous = current;
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		||||
        }
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		||||
        current.next = this.head.next;
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		||||
        this.head.next.previous = current;
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		||||
        // this.head.next = this.current; // 不能多重赋值,赋值语句会返回undefined
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		||||
        this.head.previous = current;
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		||||
    }
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		||||
    remove(node) {
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        node.previous.next = node.next;
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		||||
        node.next.previous = node.previous;
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		||||
        // delete node; // JavaScript里应该无法直接删除
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		||||
        this.length--;
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		||||
        return true;
 | 
			
		||||
    }
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		||||
 | 
			
		||||
    // 找到从当前结点开始第n个结点(可以为负数),当前结点是第0个
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		||||
    // 并且再向后返回一个结点
 | 
			
		||||
    get_n_after_node(node, n) {
 | 
			
		||||
        let property_name = "next";
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		||||
        if (n < 0) {
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		||||
            property_name = "previous";
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		||||
            n = -n;
 | 
			
		||||
        }
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		||||
        if (this.length < 3) return false;
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		||||
        for (let i = 0; i < n; i++) { // 向后走n个,例如从0开始,到3结束
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		||||
            node = node[property_name];
 | 
			
		||||
        }
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		||||
        return node;
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		||||
    }
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		||||
}
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function main(people_num, num1, num2) {
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    let link_list = new LinkList(people_num);
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		||||
    let current = link_list.head;
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		||||
    let temp;
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		||||
    while (true) {
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        temp = link_list.get_n_after_node(current, num1);
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        if (!temp) break;
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		||||
        current = temp;
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        link_list.remove(current);
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        temp = link_list.get_n_after_node(current, num2);
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        if (!temp) break;
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		||||
        current = temp;
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		||||
        link_list.remove(current);
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		||||
    }
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		||||
    // 此时current是最后一个被删掉的结点,它的next和previous都是存在的结点
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		||||
    current = current.next;
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		||||
    link_list.head.next = current;
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		||||
    for (let i = 0; i < link_list.length; i++) {
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		||||
        console.log(current.value);
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		||||
        current = current.next;
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		||||
    }
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		||||
}
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		||||
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function input(prompt) {
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		||||
    return new Promise((resolve) => {
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		||||
        rl.question(prompt, (answer) => {
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		||||
            resolve(answer);
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		||||
        });
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		||||
    });
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}
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function visualize(dryrun, link_list) {
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    if (dryrun) {
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        return;
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    }
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    let result = {
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        "kind": { "graph": true },
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        "nodes": [
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		||||
        ],
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        "edges": [
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		||||
        ]
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		||||
    };
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    let current = link_list.head.next;
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		||||
    for (let i = 0; i < link_list.length; i++) {
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        result.nodes.push({
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            "id": String(i),
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            "label": String(current.value)
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		||||
        });
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        current = current.next;
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		||||
        result.edges.push({
 | 
			
		||||
            "from": String(i),
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		||||
            "to": String(i + 1)
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		||||
        });
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		||||
    }
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		||||
    result.edges[result.edges.length - 1].to = "0";
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    return result;
 | 
			
		||||
}
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		||||
 | 
			
		||||
 | 
			
		||||
async function main_() {
 | 
			
		||||
    visualize(true); // 不加这行可能它转化成Promise的时候不会放到闭包作用域里。
 | 
			
		||||
    people_num = parseInt(await input("输入人数"));
 | 
			
		||||
    num1 = parseInt(await input("输入第一个数字"));
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		||||
    num2 = parseInt(await input("输入第二个数字"));
 | 
			
		||||
    main(people_num, num1, num2);
 | 
			
		||||
    rl.close();
 | 
			
		||||
}
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		||||
 | 
			
		||||
main_()
 | 
			
		||||
 | 
			
		||||
// 输入人数10000
 | 
			
		||||
// 输入第一个数字123
 | 
			
		||||
// 输入第二个数字-654
 | 
			
		||||
// 1299
 | 
			
		||||
// 4114
 | 
			
		||||
 | 
			
		||||
// 输入人数99999
 | 
			
		||||
// 输入第一个数字-848
 | 
			
		||||
// 输入第二个数字-351
 | 
			
		||||
// 80178
 | 
			
		||||
// 23680
 | 
			
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